Physic - 4
Topic 4


The spring balance will have different readings on the Earth and Moon. However, the beam balance will still read the same. Explain.


Alright, this presentation was done by my group. I'll do my best not to be bias(:






Above is a picture of a spring balance.

Definition of a spring balance:

It measures weight not mass.

It meaures in N(newtons).

As we all know, weight changes due to gravity, right?

So, when we're at the moon, our weight would of course be different from our weight on earth.






Above is a picture of a beam balance.

Definition of a beam balance:

It measures the mass of an object, not the weight of an object.

Mass is the amount of matter within our body and does not depend on thegravity pull from the e
earth.

Therefore, when we use beam balance at the moon to measure mass, nothing will change! EUREKA! (:

----------------------------------------------------------------

What I have learnt:

You guys know what? I didn't know beam balance actually looked like that! Only when i searched on the net>.<>
Earth is really amazing, I'm really mesmerised by how the solar system was formed billions and billions years ago. It's really amazing. I just want to go out of the point for a while.

: I believe everyone sees stars every single night right? Right;p. Since the Sun is a star, I would always think about the stars above us, shining brightly at us are Sun of other solar system too. Ah, maybe you guys have thought of it before, but I still want to continue about this(: Stars are beautiful(: I have always heard of stuff like the sun's going to die and explode someday. Sometimes when I looked up to the sky, occasionally i'll see stars shining for a while and then not anymore. Is it because the sun is going to explode or something? Hey, this is really cool! Don't you think so? (: Ok, i shall end my blabber here.:

Oh! There's such thing as artificial gravity? That's so cool(:

ok, i'll end this here, next post coming up.(:



Physic - 3
Topic 3

There are 10 000 small screws. They are to be placed in packets of 50. Manual labor is banned.What are the ways that can be used.

Method 1:Electromagnet
Adjust the voltage(resistance) of the electromagnet to pick up the amount og screws that you want.

Method 2: Using a the weighing method
Grab 50 screws and put them on a weighing machine. Take down the mass of the srews.
The next step would be taking approximately 50 screws in one grab. Take in/out the extras or insufficient.

About the first method:
Even if we adjust the voltage of the electromagnet, we still can't determine how many screws it can pick up at one shot. When the voltage is too low, we might not be able to attract any screws at all. Like wise, if the voltage is to high, too many screws will be attracted to the electro magnet resulting the imbalance of number. However, this method might be faster than the second method mentioned above.

About the second method:
Grabbing 50 screws at a time might be very time consuming. What happens if each time we grab the screws, the numbers will be over estimated or under estimated? We would have to recount everything again. Isn't this the same as counting every single screw?

ps: i'm not criticising anything(: i'm just expressing my views(:

I feel that if someone invents something like this:
A machine with 50 holes that fits screws 'head' just right. And that the machine would pick up that 50 screws 'stuck' in that machine and it would bring the screws to another place for packaging. However, the screws would have to be all in upright position, if not, the results would be still the same as the above methods mentioned. Packaging would come in place after the machine drop the screws into one place. Only 50 screws are in that place at one time to prevent confusion.

Ok, i think my suggestion sounds off. Give me suggestions? (:

Will still be blogging on the next one. ~coming up~

Physic - 2
Topic 2

You are given a length of copper wire with a small diameter. The only instrument available ot you is the metre ruler. Explain how you would measure the diameter of the wire with an acceptable degree of accuracy.

Solution:
n--number of turns
d--diameter*
*the thickness of the wire is diameter*

l = nd
l --length of coiled wire
Example:
There are 4 turns. The length of the coiled wire is 4 cm.
4 cm = 4 d
d = 1cm
------------------------------------------------------------------

Seriously, I don't get what they were trying to say. I don't undertstand!!):
I'll blog about my solution and undertstanding of ths question tomorrow(:
*promise*

Physic - 1
This shall be my Science online journal from now on(:





Presentations were done by most of my classmates during science lessons on Thursday and the week before. These are the things that I have gathered.





Topic 1:


To appreciated our limited water source, you're given a map that shows MacRitchie Reservoir.


How do you estimate the volume of water available during the dry season when the average depth of the water is 2.5m?




There are 2 solutions to this question:


Solution 1:
Area of cuboid = Length x Breadth x Height
1cm --- 60 000cm
Depth: 250cm
Length: 120 000cm
Breadth: 84 000cm
250 x 120000 x 84000
= 2520000000000 cm³
= 2520000000000ml
= 25.2 giga ml

Solution 2:
Area of cylinder: π x radius x radius x height
radius : 125cm
height : 15000cm
π : 3.14
3.14 x 125 x 125 x 15000
=7359375 thousand ml

------------------------------------------------------------------------------------------

The working to this question is really tough and tedious. However, if we compare these two methods to the 'tick' method, I would definitely use the above ones(:
What I have learnt: Science aren't just science only. Sometimes we use math in science too. Sometimes the other way round too(:

will continue my next post.